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 #1
avatar+9460 
+3

From the intersecting chord theorem, we know that.....

 

XT * TY  =  AT * TB

                                            The problem tells us that  XT = 4,  TY  =  6 ,  and  AT = 2(TB) .

4 * 6  =  2(TB) * TB

24  =  2(TB)2

                                            Divide both sides by  2  .

12  =  (TB)2

                                            Take the positive (since TB is a length) square root of both sides.

√12  =  TB

 

 

AT  =  2(TB)

                                            We know that  TB = √12

AT  =  2√12

 

 

AB  =  AT + TB

                                            Plug in the values we know for  AT  and  TB .

AB  =  2√12 + √12

                                            Combine like terms.

AB  =  3√12

                                            We can simplify  √12  since  √12  =  √(2 * 2 * 3)  =  √(22) * √3

AB  =  3(2√3)

AB  =  6√3

8 sept 2017
 #2
avatar+9460 
+2

Depending on your browser, you may be able to right click and select  "Open Image in New Tab" or "View Image" or "Properties" and then go to this address:

 

https://web2.0calc.com/api/ssl-img-proxy?src=%2Fimg%2Fupload%2F439974ca3776d9a4816e3b d7%2Fscreenshot-2017-09-08-at-4.34.05-pm.png

 

But also...to the Guest who asked the question, I suggest typing the questions if the image is small.

 

 

Sakda runs a basketball program. On the first day of the season, 55 young women showed up and were categorized by age level and by preferred basketball position, as shown in the accompanying table. Using the set labels (letters) in the table, find the number of players in each of the sets below.

 

(a) J ∩ G                     (b) S ∩ N                              (c) N U (S ∩ F)

(d) S' ∩ (G U N)          (e) (S ∩ N') U (C ∩ G')          (f) N' ∩ (S' ∩ C')

 

 

We can't see the accompanying table, so we can't answer the question.

8 sept 2017