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In an alternating-current circuit, the voltage E is given by E=IZ, where I is the cirrent (in A) and Z is the impedance.

If I=0.729-0.139j amperes and Z=260+110j ohms, find the complex-number representation.
E=
 Feb 28, 2014
 #1
avatar+118587 
0
lila7339:

In an alternating-current circuit, the voltage E is given by E=IZ, where I is the cirrent (in A) and Z is the impedance.

If I=0.729-0.139j amperes and Z=260+110j ohms, find the complex-number representation.
E=



E = (0.729 - 0.139j) (260+110j)

= 189.54 - 15.29*-1 + 30.69j - 36.14j

= 204.83 - 5.45j

I think that is alright but I could have made a stupid mistake - you had best check it.
 Feb 28, 2014
 #2
avatar+33603 
+3
Melody:
lila7339:

In an alternating-current circuit, the voltage E is given by E=IZ, where I is the cirrent (in A) and Z is the impedance.

If I=0.729-0.139j amperes and Z=260+110j ohms, find the complex-number representation.
E=



E = (0.729 - 0.139j) (260+110j)

= 189.54 - 15.29*-1 + 30.69j - 36.14j

= 204.83 - 5.45j

I think that is alright but I could have made a stupid mistake - you had best check it.




The method is right but I think you've made a small slip in the imaginary part.
Complex.PNG
 Feb 28, 2014
 #3
avatar+118587 
0
Thanks Alan, much appreciated.
 Feb 28, 2014

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