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5(3)^2/2-3+25(7)-15/3}*4/12-6

 28 nov 2014
 #1
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$${\frac{{\mathtt{5}}{\mathtt{\,\times\,}}{\left({\mathtt{3}}\right)}^{{\mathtt{2}}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{25}}{\mathtt{\,\times\,}}\left({\mathtt{7}}\right){\mathtt{\,-\,}}{\frac{{\frac{{\mathtt{15}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{4}}}{{\mathtt{12}}}}{\mathtt{\,-\,}}{\mathtt{6}} = {\frac{{\mathtt{1\,121}}}{{\mathtt{6}}}} = {\mathtt{186.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

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 2 dic 2014

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