A pair of consecutive integers has the property that 8 times the lesser is more than 4 times the greater.
Find the least pair of integers with this property.
what I did was:
8x>4(x+1)
x=1
did I do this correct??
Not QUITE correct Guest ....
8x > 4(x+1)
8x > 4x + 4
4x > 4
x > 1 Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2 and the other number is 3
If x = 1 then the left hand side is 8x1 → 8 and the right hand side is 4(1 + 1) → 8, so the left hand side is not greater than the right hand side.
Not QUITE correct Guest ....
8x > 4(x+1)
8x > 4x + 4
4x > 4
x > 1 Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2 and the other number is 3