BasicMaths

Guest, here are some easy identities for simplifying quadratics.

First, if a quadratic is in the form a^2 - b^2, then the form of the factored equation would be (a+b)(a-b). This is called the difference of squares.

Second, if in the normal quadratic form of ax ^2 + bx + c, then one must find a number that adds up to b, and multiplies to c. If a is a coefficient of a > 1, then one must find a number that adds to b and multiplies to ac. 
 

Hope this helps!

BasicMaths

Ok, so let me work this out:

If I square the stuff inside parentheses I get 0.25 + sin(theta) + sin^2(theta)-sin^2(theta).

The sin squares cancel, giving us 0.25+sin(theta). This is good so far, but this is where I got stuck last time.........Help!

Sorry melody :( here is the link for whoever wants to help :) https://web2.0calc.com/questions/precalculus-help_1

Lol hi :) (why hasn't anyone answered my question after 2 whole days.....🧐)

Thank you!

Not necessarily, Nickolas. Someone may answer a problem, but if they don’t figure out the steps and keep them stored in their brain, then it’s useless. That’s why it’s better to show someone the steps to a problem rather than giving them the answer, especially if the person hasn’t attempted it themselves and are just being lazy. Here we go back to the old phrase: If you give a man a fish, you’ll feed him for a day. Teach him how to fish, you’ll feed him for a lifetime.

Yes, so as a current AoPS Academy student, I can verify that this website has a TON of AoPS Academy homework questions. The sad thing is, this website is constantly being exploited because the people asking don’t CARE about how to solve the question; they just want the answer. Having taken AoPS classes from PreAlgebra through PreCalculus this year at the first AoPS Academy site, I can personally testify about how the classes are a mental and emotional test. However, that does mean that some students will cheat in order to keep up their good grades for their parents. So yeah, I don’t think that BANNING or completely ignoring these people would be the right solution, but rather giving them hints to solve the problem instead of the answer right off the bat. 

Day is going great! Happy to be alive.

Wow, only a few hours and I am credited! Thanks, Nirvana!

Hello!

So when we distribute all the variables in (Ax+1)(Bx+5), we get ABx^2+5Ax+Bx+5. Therefore, AB has to equal 6, and 5A+B has to equal 17. So the answer is 6, and we can check this by finding the values of A and B. These come out to be 3 for A and 2 for B. Hope this helped!