idontknowhowtodivide

The difference between 1/3 and 1/4 is 1/12. On a number line, there should be four sections each seperated from each other by 1 fraction. The distance between each fraction therefore should be 1/(12*4)=1/48. Then our new fractions can be found as 13/48,14/48, and 15/48. (13+14+15)/48=42/48=7/8

Just noticed a small error, b=-4a,not -2a. Thanks!

I'm facing another problem now -  I got the quadratic equation -8/9x^2+16/9x+1/9=y, but the axis of symmetry is x=1, not x=2. 

Written as a complex number, the answer is -242+110i

(11-5i)(11i)(2i)=

(11*11i-5*11i²)*2i=

(55+121i)(2i)=

(55)(2i)+(121i)(2i)=

110i-242=

-242+110i

(4-5i)(5+5i)=4(5)+4(5i)-5i(5)-5i(5i)=20+20i-25i-25i^2=20-5i-25(-1)=20-5i+25=45-5i is your answer.

We can use the trailing zeroes trick. 

We can divide 25! by each power of 5. 

25/5=5. But since we don't include the first multiple of 5, there would be four fives. So this would get 4 zeroes.

Now we can divide by 25, or 5^2. This gets an additional one more zero.

This then gets 5 trailing zeroes.

k=14

Explanation:

First, put the like terms on the same side. 6a+4b=k-4b turns into 6a+8b=k

Then you can multiply the top equation by 2 to get 6a+8b=14

Now, you have the system of linear equations, 

{6a+8b=14,

{6a+8b=k

Therefore, k must be equal to 14.

I got the answer as [-1/2, 1/20]. 

But isn't -20*1/2=-10? That falls into the interval, which we don't want.

There are 42 even divisors of 7!+6!.