Jamesaiden

= \(\frac{7\times 10^{23}}{100}\)

= \(7\times 10^{21}\)

4/6*150 = 100

\(6\times 14\times 12=1008\)

\((1-\frac{50}{100})\times 1008=\frac{1}{2}\times 1008=504\)

y = -2x + 20

6x - 5y = 12

6x - 5(-2x + 20) = 12

6x + 10x - 100 = 12

16x = 112

x = 7

y = -2x + 20​

y = -2*7 + 20

y = 6

1 + 2 + 3 + ... + 8 = 36

factor of 36 between 1 and 10 : 2, 3, 4, 6, 9

total : 5

Here is the picture

\(\angle A=\angle B=\angle C=60^\circ \)

tringangle ABC is an equilateral triangle because AC, AB, BC are all radius, so the length is same

The length of the common chord :

\(2\times \sqrt{10^2-5^2}=2\times 5\sqrt{3}=10\sqrt{3}\)

\(\frac{12}{100}\times 125=\frac{12}{4}\times 5=3\times 5=15 \)

t(-4) = -3 - 2*(-4) = -3 + 8 = 5

t(5) = -3 - 2*5 = -3 - 10 = -13

= \(\frac{1}{3}\times \pi \times (16-12)\)

= \(\frac{4}{3}\pi\)

length of edges a cube : 156/12 = 13

volume = 13^3 = 2197