Mathlord

tysmmm 

thx for trying, but i dont think thats right. Could u plz show how u did it? sry

Is this from LMT? cuz it feels so familiar

First we find the probability that the first card is a king and that is 4/52 = 1/13. Then we find the probability that the second card is a queen, which is 4/51 because you already took the king out. If this is wrong then it is probably because there is replacement in this solution I am assuming that there is no replacement.

Are u asking for the odds or for the fraction the fraction is 1/6188

Notice, they the appear the same number of times in each group of 100 from 0 - 399

4 14 24 34 40 41 42 43 44 45 46 47 48 49 54 64 74 84 94

8 18 28 38 48 58 68 78 80 81 82 83 84 85 86 87 88 89 98

They each appear 20 times in each group of 100

But starting at page 400 to page 488, the 4's appear

89 + 19 times   = 108 times

But the 8's only  appear 18 times  from pages 400 - 488

So the 4's appear   108  - 18    = 100 more times

In this problem because A - B = C + D, A has to be pretty big. So we start trying some cases in which A is big. First we try A = 10, so B has to equal 6. 10 -6 = 4. No 2 positive integers that multiply to 60 add up to 4. Next, we try 15 if A is 15 then B is 4，15 - 4 = 11 the smallest factor sum is 6 and 10 which adds up to 16 so that isn't right. Finally, we try A = 20 B = 3, 20 - 3 = 17. 12*5 = 20 and they add to 17 so we have found the answer. A = 20.

x =  -(√6) + 4  x = (sqrt6) + 4

You start off by subracting one fourth of the houses so 3/4 of the houses are left. 3/4 of 3/4 is 9/16. 3/4 - 9/16 = 3/16. 3/16 of 64 is 12.

10÷2/3 = 10*3/2 = 15

ok, thanks

For this problem you can work backwards. If it is 6 years after Jacob is three times his age. First, subtract 6 from 39. 39 - 6 = 33. Then, divide by 3,     33÷3 = 11. So his age is 11.

g(2) = 2(2^2) + 2(2) - 1 which equals 11. g(11) = 2(11^2) + 2(11) - 1 which is 263.

the 2 fractions aer 1/4 and 2/3. If u check this 1/4 * 2/3 is 2/12 which equals 1/6. If u add the 2 1/4 plus 2/3 the sum is 11/12.

The probability that this will happen is 1/54. If you count the numer of ways you can get 18 and 17, (6,6,6),(6,6,5),(6,5,6),(5,6,6) that is 4 ways. There are 6^3 = 216 total possibilities 4/216 = 2/108 = 1/54

the answer is 4 because in the smaller triangle the hypotenuse is twice 1 so it is 2. In the larger triangle the hypotenuse is twice 2 so 2 times 2 is 4 so x=4.

10 choose 2 is 45 because 10!/(10-2)!*2 equals 10!/8!*2 10!/8! is 90 90 divided by 2 is 45. 8 choose 3 is 56. 45*56 is 2520 so the answer is 2520.

45√3

are the triangles equilateral?