mworkhard222

Well if ur solving for x, then 2x² + 7x - 5 = -1/3x² − 2x + 9

\(2x^3+7x-5=-\frac{1}{3}x^2-2x+9\)

\(=6x^3+21x-15=-x^2-6x+27\)

\(=6x^3+21x-42=-x^2-6x\)

\(=6x^3+27x-42=-x^2\)

\(=6x^3+x^2+27x-42=0\)

\(=x\approx \:1.15942\dots \)

1????

Well fill in 3/4 every time you see x.

\(8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0\)

\(=9\)

\(\frac{x^4+7x^3+17x^2+20x}{x^2+4} \)

\(=x^2+\frac{7x^3+13x^2+20x}{x^2+4}\)

\(=x^2+7x+\frac{13x^2-8x}{x^2+4}\)

\(=x^2+7x+13+\frac{-8x-52}{x^2+4}\)

\(x^2+7x+13+\frac{-8x-52}{x^2+4}\)

is this what u are looking for?

oh ok, it going to be \(\left(7\frac{1}{6}\cdot 3\right)\cdot 7\frac{1}{6}.\) 

\(7\frac{1}{6}\cdot 3=\frac{43}{2}\) and \(\frac{43}{2}\cdot 7\frac{1}{6}=154\frac{1}{12}\)

if it could then x = 1 and 1 - 7 = -6

if not then x = 3 and 9 - 7 = 2

can y be nagative?

The chart: 

The bar chart tells us that
6 families each have 0 pets,
3 families each have 1 pet,
3 families each have 2 pets,
6 families each have 3 pets,
1 family has 4 pets, and
1 family has 5 pets.


The total number of pets in all these families is \((6\cdot 0)+(3\cdot 1)+(3\cdot 2)+(6\cdot 3)+(1\cdot 4)+(1\cdot 5)=36\). The number of families is \(6+3+3+6+1+1=20\).Therefore, the average number of pets per family is \(\frac{36}{20} = \boxed{1.8}.\)
 

The grade level in which the number of male bus riders is closest to \(135\%\) of the number of female bus riders is the same grade level in which the percentage of male bus riders is closest to \(135\%\) of the percentage of female bus riders. To find what percentage is  \(135\%\) of the percentage of female bus riders, we multiply each percentage by \(1.35.\) In ninth grade, the percentage is  \(39.4\cdot1.35=53.19\) percent. In tenth grade, the percentage is \(33.1\cdot1.35=44.685\) percent. In eleventh grade, the percentage is \(13.8\cdot1.35=18.63\) percent. In twelfth grade, the percentage is \(8.6\cdot1.35=11.61\) percent. From inspection, we see that \(135\%\) of the percentage of female bus riders in twelfth grade is closest to the percentage of male bus riders in twelfth grade. So the answer is \(\boxed{12}.\)