PikachuLovesKetchup

 XD

Yes, but then again, I drew it wrong. I got help from my dad; I managed to solve it! Thanks!

~ PikachuLovesKetchup

Thanks! It helped a lot!(I forgot about using theorems literally)

~ PikachuLovesKetchup

Cool, thanks!

Can you explain, -10/13 as the slope? Oh wait, nevermind

Thanks guys! I appreciate it!

First we know that ABC is an isosceles triangle. On line AB, there is a point P that makes CPB an isosceles triangle as well. Angle APC is 116. That means angle CPB is 180-116=64 degrees. Since triangle CPB is isosceles, angle PBC is also 64 degrees. That makes angle PCB 180-(64+64)=180-128=52 degrees. As you may recall, triangle ABC is isosceles, so angle ACP+52=64. Solving for the angle, we get ACP=64-52=12 degrees. (By the way, sorry there's no picture to show you my thinking.)

How do you delete a post?

For some reason, I can't see my own question. How do I fix it? I mean, I can see my answer, but not my question. I am really confused.

I don't know how to write in LaTeX in web2.0calc.com, so I'm going to try without it.

Set variables for the number of dimes and the number of quarters. The number of dimes can be d, and the number of quarters can be q. We already know there are TWICE the amount of dimes than quarters. So, we can say d=2q. since they have cost, we must multiply d or 2q by 10, and q by 25. My work is below:

20q+25q=630(in cents!!!!!) 45q=630(I used a calculator to do 630/45) q=14. 2q=28.

Check: 20(14)+25(14)=630(I used a calculator to do 25•14) 280+350=630. 630=630.

So, Jack has 28 dimes. :)