+73 11.)
a.) Evaluate j(-1) given j(x) = 2x4 - x3 - 35x2 + 16x + 48.
2(-1)4 - (-1)3 - 35(-1)2 + 16(-1) + 48 = 0
2 + 1 - 35 - 16 + 48 = 0
b.) Explain what your answer tells you about x + 1 as a factor.
It tells you that when the binomial x + 1 is divided with j(x) then is it divided equally with a remainder of 0 so it is a factor.
c.) Algebraically find the remaining zeros of j(x).
+118608 Nice presentation GameMaster, I am impressed with your new style of delivery :)
You know that x+1 is a factor so if you divide j(x) by x-1 you will find at least one more factor.
I have done it to check that it works nicely but I want you to the the division for yourself.
I just used normal algebraic long division but i suppose you could use synthetic division if you know that method.
Anyway, after you do that it is relatively easy to break the new factor into 3 to get all the factors.
Once you have the factors you can get the zeros very easily.
Give it a go and if you get stuck then explain to us what your problem is 
+12527
b.) Explain what your answer tells you about x + 1 as a factor.
It tells you that when the binomial x + 1 is divided with j(x) then is it divided equally with a remainder of 0 so it is a factor.
c.) Algebraically find the remaining zeros of j(x).
