(2)^(1/3) * (14)^(1/3) = (28)^1/3
We use the fact that \(\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}\) to get that \(\sqrt[3]{2} \cdot \sqrt[3]{14} = \sqrt[3]{2 \cdot 14} = \boxed{\sqrt[3]{28}}\).
Hoping this helped,
asdf334
