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3π‘₯^2 βˆ’ 4π‘₯ βˆ’ 2 = 0 has solutions π‘₯ = 2±√10/ 3

 Sep 23, 2018
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Hmmmm..... Using Quadratic Formula   I get   (4+- 2sqrt10)/3

 Sep 23, 2018
edited by ElectricPavlov  Sep 23, 2018

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