The probability of drawing two red candies without replacement is 13/35 , and the probability of drawing one red candy is 2/5 .
What is the probability of drawing a second red candy, given that the first candy is red?
+981 Alright, here we go:
To draw two red candies without replacement is 13/35, but since drawing the first red candy is 2/5, drawing the second one, must be:
\(\frac{13}{35}\div\frac{2}{5}=\frac{13}{14}\)
+118608 The probability of drawing two red candies without replacement is 13/35 , and the probability of drawing one red candy is 2/5 .
What is the probability of drawing a second red candy, given that the first candy is red?
\(\frac{2}{5 }x=\frac{13}{35}\\ x=\frac{13}{35}\div \frac{2}{5 }\\ x=\frac{13}{35}\times \frac{5}{2 }\\ x=\frac{13}{14} \)
