A, B, C, and D are positive digits such that ABCD + BCD = 2012. Find A + B + C + D.
+208 D+D=12
D=6
C+C=10
C=5
If C=5, then 2B either equals 9 or 19. I don't know if you wrote the question right, since B either equals 4.5 or 19?
If you get rid of the "positive", and they are simply nonnegative, then it's possible:
D=6
B=0
C=0
A=2
A+B+C+D=8
Correct me if I'm wrong though
+208 D+D=12
D=6
C+C=10
C=5
If C=5, then 2B either equals 9 or 19. I don't know if you wrote the question right, since B either equals 4.5 or 19?
If you get rid of the "positive", and they are simply nonnegative, then it's possible:
D=6
B=0
C=0
A=2
A+B+C+D=8
Correct me if I'm wrong though
