What are the first 10 digits after the decimal point in the expansion of this expression: [(sqrt (3) + sqrt(2)]^2002 ?. Thank you.
Using a calculator, I got .... 9.9998575128 are the ten digits after the decimal point.
+266 \([(\sqrt (3) + \sqrt(2)]^{2002}\)
alright so the first ten digits of the decimal expansion.
just plug it in to a calc and u should be able to get it
(sqrt(2) + sqrt(3))^2002 =3854913 6553434375 7852540977........... 4542810952 6835265508 6915760009.9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999999999 9999997405 908
So, the first 10 digits after the decimal point are:9,999,999,999
