There are three independent events with probabilities of 1/3, 2/7, and 1/4. Find the probability that: Exactly one event will happen.
TY
You can use the principle of inclusion and exclusion. 1/3+2/7+1/4-(1/3*2/7)-(1/3*1/4)-(2/7*1/4)+(1/3*2/7*1/4)=9/14
:D
+130 
