What is the equation of a line that is perpendicular to y= 3x-2 and passes through the point 6,8
Slope of the line you are given = 3 perpindicular is -1/3
so far you will have y = -1/3 x + b put in the point given for x and y to compute 'b'
8 = -1/3 (6) + b so b = 10
the line you are looking for becomes y = -1/3 x + 10