help! please! .....

Question

0

750

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+4609

The vertices of a convex pentagon are \((-1, -1), (-3, 4), (1, 7), (6, 5)\) and \((3,-1)\) . What is the area of the Pentagon?

tertre Mar 21, 2018

+9466

+3

Best Answer

Here's one way.....

We can break the shape up into right triangles and rectangles, then get the area of each piece.

Remember the area of a triangle = (1/2)(length of base)(height)

Add the areas together...

6 + 5 + 2 + 9 + 5 + 20 = 47 sq units

hectictar Mar 21, 2018

hectictar · Answer 1 · 2018-03-21T02:59:28

Here's one way.....

We can break the shape up into right triangles and rectangles, then get the area of each piece.

Remember the area of a triangle = (1/2)(length of base)(height)

Add the areas together...

6 + 5 + 2 + 9 + 5 + 20 = 47 sq units

Melody · Answer 2 · 2018-03-21T04:31:01

I like Hectictar's method better but here is a different way.

Divide the pentagon inot 3 triangles. Find the lengths of all the sides of all the triangles.

Then find the areas, one at a time, using Heron's formula.