An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. If two consecutive marbles are drawn without replacement what is the probability that the first one will be green and the second one will be red?
0.51
0.10
0.11
0.16
+220 In total there are 5 + 3 + 2 = 10 marbles in total
The probability that the first one drawn out 5/10 = 1/2, and the chance that the second will be red is 2/9, because there is no replacement
1/2 x 2/9 = 1/9
The probability that the first one drawn out will be green and the second one is red is 1/9
+188 Not sure if this is right, but I tried writing all the possible ways and got this:
gg, gg, gb, gb, gb, gr, gr, bb, br, br, rr, bg, bg, bg, rb, rb
Each g represents a green marble, r for a red marble, and b for a blue marble
there are 2 green-reds (gr) and 18 possible marble color choices, which gives us 2/18 and when simplified is 1/9
