Let \[f(x) = \frac{3x - 7}{x + 1}.\] Find the inverse $f^{-1}(x)$.
\(f(x) = \frac{3x - 7}{x + 1}\)
Write
y = [ 3x - 7] / [ x + 1] get x by itself
y [ x + 1] = 3x - 7
yx + y = 3x - 7
y + 7 = 3x - yx
y+ 7 = x (3 - y)
[y + 7 ] / [ 3 - y ] = x "swap" x and y
[ x + 7 ] / [ 3 - x ] = y = f-1(x)
What is the inverse?
