Suppose (x,4) is a point on the line that passes through the point (-3,0) with slope 1/2. Find x.
\(slope = \dfrac{y_2-y_1}{x_2-x_1} = \\ \dfrac{4-0}{x-(-3)} = \dfrac 1 2\\ \dfrac{4}{x+3}=\dfrac 1 2\\ 8 = x+3\\ x = 5\)
Thanks Rom!
+505 
