+1206 If we express \(-2x^2 + 4x + 5\) in the form \(a(x - h)^2 + k\), then what is \(k\)?
+128408 -2x^2 + 4x + 5 factor out the "-2"
-2 ( x^2 - 2x - 5/2)
Complete the square on x......take (1/2) of 2 = 1....square iy 1^2 = 1....add and subtract it within the parentheses
-2 ( x^2 - 2x + 1 - 5/2 - 1) factor the first three terms in the parentheses.....simplify the rest
-2 [ ( x - 1)^2 - 7/2 ] distribute the "-2"
-2 ( x - 1)^2 + 7
k = 7
