In right triangle ABC with \(\angle B = 90^\circ\), we have \(\sin A = 2\cos A\). What is \(\cos A\)?
Sin a = 2 cos a
sin a / cos a = 2
arctan 2 = 63.44 degrees
Ooops sorry.... I gave ypu the angle, not the cos
cos 63.44 = .447
Chris' answer below is the EXACT value..... ~ EP