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Given that 2^x=7, find the value of 4^(x-1).

 Aug 15, 2020
 #1
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+4

We can rewrite 4^(x-1) as 4^x/4. 4^x can be rewritten as (2^x)^2, which is 7^2, which is 49. So, the answer is 49/4, which is 12.25 in decimal form.

 

:)

 Aug 15, 2020

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