Compute \(\tan 300\) and \(\tan 60\)
tan300=-sqrt3 and tan60=sqrt3 so we have \(\tan 300=-\sqrt3~~and~~\tan 60=\sqrt3\)
is this correct
This is correct thanks jimkey17
Remember tan = sin / cos so for 60o tan 60 = sqrt3/2 / 1/2 = sqrt 3
tan 300 = -sqr3/2 / 1/2 = - sqrt 3
+1262 
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