+4 the question says that
p>q>0
find the length of the line segment joining these paris of points.
(p , q) and (q , p)
these are the coordinates.
there must some formula or something that i dont know.
\(\sqrt{(p-p)^2 + (q-q)^2}\)
and if the answer from the back of the book is required i will post it
ALL HELP IS DEEPLY APRECIATED
+26367 the question says that
p>q>0
find the length of the line segment joining these pairs of points.
(p , q) and (q , p)
these are the coordinates.
\(\begin{array}{|rcll|} \hline \text{length} &=& \sqrt{(p-q)^2+(q-p)^2} \\ &=& \sqrt{(p-q)^2+\Big(-(p-q)\Big)^2 } \\ &=& \sqrt{(p-q)^2+\Big( (-1)(p-q) \Big)^2 } \\ &=& \sqrt{(p-q)^2+(-1)^2(p-q)^2 } \quad & | \quad (-1)^2 = 1^2 = 1 \\ &=& \sqrt{(p-q)^2+1\cdot(p-q)^2 } \\ &=& \sqrt{(p-q)^2+(p-q)^2 } \\ &=& \sqrt{2\cdot (p-q)^2 } \\ &\mathbf{=}& \mathbf{(p-q)\sqrt{2}} \\ \hline \end{array}\)
+118608 Thanks Heureka,
Scarface, the formula that you used was incorrect. Heureka's one is right.
This is the formula that it comes from
distance = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
this is the distance forumla which kids are told to learn.
It looks horrible but it is just Pythagoras's theorum. :)
