If $a \text{ Y } b$ is defined as $a \text{ Y } b = a^2 - 2ab + b^2$, what is the value of $3 \text{ Y } 2$?
Answer: 1
\(3Y 2\) means that a = 3 and b = 2.
Then, we can plug in and solve. 3^2 - 2 * 3 * 2 + 2^2 = 9-12+4 = 1.
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