If \(z\) is twice \(x\) , then what is \(5x+10+z-10+2z\) in terms of \(x\) ?
+10 If you simplify the question then you will get 11x.
Z=2x
Write the problem out and then substitute the z for 2x.
5x +10+z-10+2z
5x + 10+ 2x-10 +4x
The two tens cancel out cause their negative and positive.
5x +2x+4x
Add the the variables
11x is your answer
