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The equation \(y = -4.9t^2 - 3.5t + 2.4\) relates the height \(y\) (in meters) to the elapsed time \(t\) (in seconds) for a ball thrown downward at 3.5 meters per second from a height of 2.4 meters from the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest hundredth.

 Mar 17, 2019
 #1
avatar+122 
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Set the equation equal to 0. 

0=-4.9t^2-3.5t+2.4

Solve! I think you can take it from here!

HOPE THIS HELPS smiley

 Mar 17, 2019
 #2
avatar+4 
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Well yes, you are technically correct but what about the decimals. Wouldn't the answer turn out to be some crazy decimal with \(i\).

CrazyHelp  Mar 17, 2019
edited by CrazyHelp  Mar 17, 2019
 #3
avatar+4 
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Nvm, I didnt see the negative sign.

CrazyHelp  Mar 17, 2019

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