In how many ways can seven beads of distinct colors be put on the hexagonal grid shown, if reflections and rotations of an arrangement are c

I also need help on this.

I am not sure but this is what i am thinking

Any on of the 7 can go in the middle 

Place one more is a specific spot - Say the red one 

There are 5 more places to fill so that is 5!

Now if the middle one and one side one is fixed then there is only one axis of symmetry that counts,  I mean the one that goes through the centre one and the red one.

So maybe the answer is

\(\frac{7*5!}{2}=7*3*4*5=420\)

I am ot sure though.

Asked again here

https://web2.0calc.com/questions/help-with-this-question-https-web2-0calc-com-questions

But please answer on the original post, that is the one of have attempted the answer on.