If \(\frac{^5log2}{^5log3}=m\) , then \(2^{2m}+2^{m+2}=?\)
Thank you very much for helping me.
The little 5 is derived from the question itself. I don't know if the question is wrong from the beginning or not. But that what the question is. I can post a picture of it if you want.
Note : i am not a native english speaker, i am very sorry for any mispell or miscommunication. I just need help :(
+118609 Well the 5 does not make sense but lets look at a possible meaning.
Note that when an English speaking person sees \(log_25\)
They would SAY it as log of 5 base 2 or log 5 base 2
\(m=\frac{log_25}{log_35}\\ m=\frac{log5}{log2}\div \frac{log5}{log3}\\ m=\frac{log5}{log2}\times \frac{log3}{log5}\\ m=\frac{log3}{log2}\\ mlog2=log3\\ log2^m=log3\\ 2^m=3\\~\\ \)
\(2^{2m}+2^{m+2}\\ =(2^m)^2+2^m*2^2\\ =3^2+3*4\\ =9+12\\ =21 \)
If the pic looks a little different perhaps you should post that 
