A cylindrical can of internal radius 20 cm stands upright on a flat surface. It contains water to a depth of 20 cm. Calculate the rise in the level of the water when a brick of brick of volume 1500cm3 is immersed in the water.
Hi Rauhan
A cylindrical can of internal radius 20 cm stands upright on a flat surface. It contains water to a depth of 20 cm. Calculate the rise in the level of the water when a brick of brick of volume 1500cm3 is immersed in the water.
A really important thing to remember is that 1cm^3 holds 1mL of water.
so
a 1500cm^3 brick will displace 1500ml of water.
The original height of the water is irrelavant. Unless the water overflows.
How much height is this?
\(\pi r^2 h=Volume\\ \pi *20^2*h=1500\\ h=\frac{1500}{400\pi}\\ h=\frac{15}{4\pi}\;cm\)
h=1.193662073189215 cm
The water will rise approx 1.2cm