Six people are sitting around a circular table, and each person has either blue eyes or green eyes. Let x be the number of people sitting next to at least one blue-eyed person, and let y be the number of people sitting next to at least one green-eyed person. How many possible ordered pairs (x,y) are there? (For example, (x,y) = (6,0) if all six people have blue eyes, since all six people are sitting next to a blue-eyed person, and zero people are sitting next to a green-eyed person.)
+118608 off the top of my head...
0 to 6 for blue and 0 to 6 for green = 49
that is assuming that a person can have one green eye and one blue eye. (probably not what was intended 
)
+118608 otherwise try looking at each scenario seperately
0 blue, 6 green
1 blue, 5 green
etc
Some are easy some will be hard.
Show us what you can do on your own.
No one else do this problem for guest. Thanks.
@melody it's more difficult then you stated in problem 2. I'm not sure about this either, but here's nine possible (x,y)'s:
1. (0, 6)
2. (2, 6)
3. (4, 6)
4. (3, 5)
5. (5, 5)
6. (6, 4)
7. (5, 3)
8. (6, 2)
9. (6, 0)
NOTE: 1 is not a possible value of x or y
Wait I found 2 more.
1. (6, 0)
2. (6, 2)
3. (6, 3)
4. (6, 4)
5. (5, 3)
6. (5, 5)
7. (4, 6)
8. (3, 5)
9. (3, 6)
10. (2, 6)
11. (0, 6)
+118608 I did not say it was easy, I said parts of it were easy and I gave a start point
this is exactly what i said.
Try looking at each scenario separately,
0 blue, 6 green
1 blue, 5 green
etc
Some are easy some will be hard.
Show us what you can do on your own.
Did guest show what he could do on his own?
OR did you just race in and give him an answer? (which may or may not be correct)
I should not sound too negative about it, if the question inspired you to practice or learn something then your effort is of value (to you)
Your answer only has cheat value to the asker however.
