+1993 I tried doing ti myself but I feel like I am way off. I think 1 is B and 2 is C
Forty slips of paper are numbered 1 through 40 and are distributed among a group of people. A random number generator is used to select a single number between 1 and 40, inclusively.
A fair decision is made using this process.
How many people could be in this group?
6
8
12
15
In a particular game, a spinner with four equally-sized sectors labeled 1, 4, 6, and 8 is spun twice. One turn is considered 2 spins of the spinner.
If the sum of the spins is even, you move forward 6 spaces. Otherwise, you move back 2 spaces.
What is the mathematical expectation for the number of spaces moved in one turn?
3 spaces backward
1 space backward
3 spaces forward
1 space forward
+6248 1) The number of people in the group must divide 40. 8 is the only selection that divides 40.
2)
Even sum pairs are (1,1),(4,4),(4,6),(4,8),(6,4),(6,6),(6,8),(8,4),(8,6),(8,8) - There are 10 of them
Odd sum pairs are (1,4),(1,6),(1,8),(4,1),(6,1),(8,1) - There are 6 of them
P[Even]=10/16 = 5/8
P[Odd]=6/16 = 3/8
E[moves] = 5/8 x 6 - 3/8 x 2 = (30-6)/8 = 3 = 3 spaces forward
+6248 1) The number of people in the group must divide 40. 8 is the only selection that divides 40.
2)
Even sum pairs are (1,1),(4,4),(4,6),(4,8),(6,4),(6,6),(6,8),(8,4),(8,6),(8,8) - There are 10 of them
Odd sum pairs are (1,4),(1,6),(1,8),(4,1),(6,1),(8,1) - There are 6 of them
P[Even]=10/16 = 5/8
P[Odd]=6/16 = 3/8
E[moves] = 5/8 x 6 - 3/8 x 2 = (30-6)/8 = 3 = 3 spaces forward
