+106 For it to be the square of a binomial, it has to be in the form:
\((r + s)^2 = 4x^2 + 14x + c\)
We find that the first term squared = 4x^2
\(r^2 = 4x^2\)
\(r = 2x\)
\((2x + s)^2 = 4x^2 + 14x + c\)
We know the second term is in the form:
\(4(x)(r) = 14x\)
\(4r = 14\)
\(r = 3.5\)
So our binomial is in the form:
\((2x+3.5)(2x+3.5) \)
So our constant "c" would be:
\(c = 3.5^2 \)
\(c = 12.25\)
(If this answer is wrong please tell me, as I would be more than happy to fix it)
