\(If $f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases}$, then for how many values of $x$ is $f(f(x)) = 3$?\)
f(f(x) ) = 2(-x + 5) - 5 = -2x + 5
f(f(x)) = 3
-2x + 5 = 3
-2x = -2
x = 1
or
f(f(x)) = -(2x - 5) + 5 = -2x + 10
-2x + 10 = 3
-2x = -7
x = 7/2 = 3.5
