Suppose \(f \) is a polynomial such that \(f(0) = 47, f(1) = 32, f(2) = -13\), and \(f(3)=16 \) . What is the sum of the coefficients of \(f \)?
\(f(x)=ax^4+bx^3+cx^2+dx+e\\ e=47\\ f(x)=ax^4+bx^3+cx^2+dx+47\\ f(1)=a+b+c+d+47=32\\ a+b+c+d=32-47\\ a+b+c+d=-15\\\)
Ths sum of the coefficients is -15
This would be true even if it the leading power was not 4.
I'm sorry but that is incorrect. Thanks for trying anyone else please help???
It is fine to say it is incorrect but please give the reason that you think so.
Why just a + b + c + d ? , isn't e a coefficient as well ?
No e is not a coefficient. e is the constant.
Coefficients are the numbers in front of the pronumerals
(if the pronumeral is 1 then it is invisable but it is still there - that is not relevant here though.)
