What is the largest number c such that \(2x^2+5x+c=0\) has at least one real solution? Express your answer as a common fraction.
+62 Since b^2 - 4ac must be greater than 0 in order to have at least one real number solution, you can plug it in:
25 - 8c > 0
8c < 25
c < 25/8
As a result, your answer is 25/8.
:D Hope this helps.
+36915 To be mathematically correct c ≤ 25/8 as the determinant can = 0
