For what value of k is the remainder 0 when the function g(x)=-3xk^3+kx-2 is divided by (x-2)?
+128474
2 [ (-3k^3 + k) - 2 ]
- 6k^3 + 2k
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-3k^3 + k -6k^3 + 2k - 2
So
-6k^3 + 2k - 2 = 0 divide through by -2
3k^3 - k + 1 = 0
Solving this with a CAS, we get that
k ≈ -.85138
+36916 Similarly, if the result is 0 when divided by (x-2) , then x = 2 is a root
sub in x = 2
-6 k^3 +2k - 2 = 0 simplify
3k^3 - k + 1 = 0
then the answer is k = -0.85138 as Chris found ......
