I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?
2x^2-4>0
x^2-2>0
x^2>2
x>sqrt2 or x<-sqrt2
I have not worked it out but I am thinking that you could let \(\theta=sec^{-1}\frac{x}{\sqrt2}\)
that should help.
"I can't figure out how to solve for ∫ sqrt(2x^2-4) / (7x). Can someone please help me?"
Like so:
(As it is an indefinite integral you should add an arbitrary constant of course.)
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Very nice, Alan!!!!
