The length of a rectangle is 6yds longer than its width. If the perimeter of the rectangle is 72yds, find its length and width.
+36914 L = 6 + w given
Perimeter = 2 * L + 2 * W
2 (6+w) + 2w = 72
12 + 2w + 2w = 72
4w = 60
w=15 L = 6+w = 21
+36914 L = 6 + w given
Perimeter = 2 * L + 2 * W
2 (6+w) + 2w = 72
12 + 2w + 2w = 72
4w = 60
w=15 L = 6+w = 21
