In square ABCD, P is the midpoint of BC, and Q is the midpoint of CD. Find sin angle APQ.
+592 https://gyazo.com/eb81f42a01d41413e5c0e2142e65f840
https://gyazo.com/8eb1c4fc84d610677733f0a49f80111e
https://gyazo.com/43b4aa667b149034c2b1db4b8e91ebbe
Here are the pictures to my working... didn't know how to explain without pictures
Hope this helps though :)
Answer ≈ 71.57o
+36915 See image below:
angle z + angle apq + 45 = 180 degree straight line
tan z = x / (1/2 x) = 2
arctan(2) = z = 63.434
63.434 + APQ + 45 = 180
APQ = 71.565 degrees
+1694 ∠APB = arctan(2/1) = 63.43494882º
∠CPQ = 45º
∠APQ = 180 - (∠APB + ∠CPQ) = 71.56505118º
sin(∠APQ) = 0.948683298 
