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Find the Dot Product of v · u

v = < 3, 8 >, u = < 2, -6 >

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need some feedback to see if i got this right. 
i got 48.37 as my final answer. 

 Jun 10, 2014

Best Answer 

 #3
avatar
+5

Thanks for the help guys!! i see where i went wrong now. 

 Jun 10, 2014
 #1
avatar+128732 
+5

Remember that if we have u = < u1 , u2 > and v = < v1 , v2 > .... the dot product is just a scalar given by:

(u1* v1) +  (u2* v2)  =  dot product

Try it again.......there shouldn't be any decimals in this answer....repost if you still have trouble.......

 Jun 10, 2014
 #2
avatar+26379 
+7

$$\\\boxed{\vec{v}*\vec{u} = \begin{pmatrix} \textcolor[rgb]{1,0,0}{v_1}\\ \textcolor[rgb]{0,0,1}{v_2} \end{pmatrix} * \begin{pmatrix} \textcolor[rgb]{1,0,0}{u_1}\\ \textcolor[rgb]{0,0,1}{u_2} \end{pmatrix} = \begin{pmatrix} \textcolor[rgb]{1,0,0}{v_1}*\textcolor[rgb]{1,0,0}{u_1} + \textcolor[rgb]{0,0,1}{v_2}*\textcolor[rgb]{0,0,1}{u_2} \end{pmatrix}}\\
\boxed{\vec{v}*\vec{u} = \begin{pmatrix} \textcolor[rgb]{1,0,0}{3}\\ \textcolor[rgb]{0,0,1}{8} \end{pmatrix} * \begin{pmatrix} \textcolor[rgb]{1,0,0}{2}\\ \textcolor[rgb]{0,0,1}{-6} \end{pmatrix} = \begin{pmatrix} \textcolor[rgb]{1,0,0}{3}*\textcolor[rgb]{1,0,0}{2} + \textcolor[rgb]{0,0,1}{8}*\textcolor[rgb]{0,0,1}{(-6)} \end{pmatrix}=\textcolor[rgb]{1,0,0}{6}\textcolor[rgb]{0,0,1}{-48}=-42}$$

 

This is wrong: $$\sqrt{(3*2)^2+(8*(-6))^2} = 48.374 \;?!$$

.
 Jun 10, 2014
 #3
avatar
+5
Best Answer

Thanks for the help guys!! i see where i went wrong now. 

Guest Jun 10, 2014

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