+209 In triangle $ABC,$ $\angle B = 90^\circ.$ Point $X$ is on $\overline{AC}$ such that $\angle BXA = 90^\circ,$ $AX = 5,$ and $CX = 5$. What is $BX$?
+14921 What is BX?
Angle B is 90°. Angle BXA is 90°.
So BX is the height of the Thales circle with radius 5.
\(\color{blue}\overline {BX}=5\)
!
