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starts at 4 increases by 3 what would be the 50 term

 May 20, 2014

Best Answer 

 #1
avatar+26367 
+7

So we have:

$$\\\mbox{start} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}$$

Latex code:

} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}

Term 50 is 151

 May 20, 2014
 #1
avatar+26367 
+7
Best Answer

So we have:

$$\\\mbox{start} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}$$

Latex code:

} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}

Term 50 is 151

heureka May 20, 2014

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