The graph of the equation .\(y =ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants, is a parabola with axis of symmetry \(x = -3\)Find \(\frac{b}{a}\).
If the axis of symmetry is x = -3, then - 3 is the x coordinate of the vertex
And....the x coordinate of the vertex is given by -b / (2a)
So we have that
-b / (2a) = -3
b / (2a) = 3 multiply both sides by 2
b / a = 6