Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
755
1
avatar

15n^2-52n+32 factor trinomial

 Oct 7, 2014

Best Answer 

 #1
avatar+23254 
+5

If you do it by trial-and-error, there are a lot of possibilities;  

15  can be factored as  (1 and 15)  or  (3 and 5)

32  can be factored as  (1 and 32)  or  (2 and 16)  or  (4 and 8)  or  (8 and 4)  or  (16 and 2)  or  (32 and 1)

Since the last term is positive, the two factors must either be both positive or both negative; since the middle term is negative, they must both be negative.

(n - 1)(15n - 32) =

(n - 2)(15n - 16) =

(n - 4)(15n - 8) =

(n - 8)(15n - 4) =

(n - 16)(15n - 2) =

(n - 32)(15n - 1) =

(3n - 1)(5n - 32) =

(3n - 2)(5n - 16) =

(3n - 4)(5n - 8) =

(3n - 8)(5n - 4) =

(3n - 16)(5n - 2) =

(3n - 32)(5n - 1) =

One of the above is correct, the problem is to determine which of the above has the correct middle term, the O and I of FOIL.

It's there ...

 Oct 7, 2014
 #1
avatar+23254 
+5
Best Answer

If you do it by trial-and-error, there are a lot of possibilities;  

15  can be factored as  (1 and 15)  or  (3 and 5)

32  can be factored as  (1 and 32)  or  (2 and 16)  or  (4 and 8)  or  (8 and 4)  or  (16 and 2)  or  (32 and 1)

Since the last term is positive, the two factors must either be both positive or both negative; since the middle term is negative, they must both be negative.

(n - 1)(15n - 32) =

(n - 2)(15n - 16) =

(n - 4)(15n - 8) =

(n - 8)(15n - 4) =

(n - 16)(15n - 2) =

(n - 32)(15n - 1) =

(3n - 1)(5n - 32) =

(3n - 2)(5n - 16) =

(3n - 4)(5n - 8) =

(3n - 8)(5n - 4) =

(3n - 16)(5n - 2) =

(3n - 32)(5n - 1) =

One of the above is correct, the problem is to determine which of the above has the correct middle term, the O and I of FOIL.

It's there ...

geno3141 Oct 7, 2014

5 Online Users

avatar
avatar
avatar