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 A ball was kicked into the air from a balcony 20 feet above the ground, and the ball’s height above the ground, in feet, t seconds after the

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A ball was kicked into the air from a balcony 20 feet above the ground, and the ball’s height above the ground, in feet, t seconds after the ball was kicked was h(t) = 20 −16t2 + 32t. What was the maximum height, in feet, of the ball above the ground after it was kicked?

math
 Aug 14, 2014

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If height, h = 20 - 16t2 + 32t, then upward velocity, v = dh/dt = -32t + 32.  At its highest point the speed is zero, so this happens when -32t + 32 = 0 or when t = 1.  At this time the height is hmax = 20 -16*12 +32*1 = 36 feet

 Aug 14, 2014

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 #1
avatar+33654 
+5
Best Answer

If height, h = 20 - 16t2 + 32t, then upward velocity, v = dh/dt = -32t + 32.  At its highest point the speed is zero, so this happens when -32t + 32 = 0 or when t = 1.  At this time the height is hmax = 20 -16*12 +32*1 = 36 feet

Alan Aug 14, 2014

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