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A committee requires one accountant, two marketing agents, and four, board members. If there are four accountants, three marketing agents, and seven board members available for selection in the committee, the number of committees that can be formes is?

 Oct 26, 2014

Best Answer 

 #2
avatar+23254 
+5

You are selecting one accountant from four, two marketing agents from three, and four board members from seven.

Since order in not important, use combinations.

4nCr1 x 3nCr2 x 7nCr4  =  4 x 3 x 35  =  420 ways

 Oct 26, 2014
 #1
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There will have to be one commity with 3 accountants, 1 marketing agent, and 3 board members.

hope it helped

-Robert

 Oct 26, 2014
 #2
avatar+23254 
+5
Best Answer

You are selecting one accountant from four, two marketing agents from three, and four board members from seven.

Since order in not important, use combinations.

4nCr1 x 3nCr2 x 7nCr4  =  4 x 3 x 35  =  420 ways

geno3141 Oct 26, 2014

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